●Endless belt dynamics culcalation

(2).From carrying weight

    Te＝ (（m1+m2）×μ1×ｇ) / η
    m1:Load weight(kg)
    m2: Steel belt weight(kg)
    μ1: Coefficient of friction between steel belt and belt support (Graph 1)

Graph1

   ｇ:Gravitational acceleration
    g ＝9.807（m／ｓ2）
    η:Efficiency between steel belt and pulley
    η＝0.9

2. Calculate tight side tension
 Tt=Te×(eμ0θ0)/(eμ0θ0-1)
 Tt:Tight side tension(N)
    e:base of natural logarithm
    e＝2.718
   μ0:friction between steel belt and pulley(Graph2)

Graph2

  θ0: Wrap angle of steel belt against pulley (rad)

 (eμ0θ0) / (eμ0θ0-1) is as per graph 3

Graph3

3.Judge if it can use or not.
  Allowable tensile unit stress ≧Tt / (t×W)
    t:Thickness of steel belt(mm)
   W:Width of steel belt(mm)
  If above formula is applicable, it can use.
  Graph 4  Allowable tensile unit stress for representative grade.

Graph4

4.Other:

Te=Tt－Ts・・・・1
Tt/Ts＝e^（μ0×θ）・・・・・2
Te：Effective tension(N)
Tt：Tight side tension(N)
Ts：Slack side tension(N)
e：Base of natural logarithms,e=2.71828
μ0：Friction coefficient of belt and pulley（0.2）※１
θ：Winding angle of steel belt against pulley（π）※2
※1．Friction coefficient of belt and pulley is based on pulley’s finish 1.6a (SUS).     It may vary by material of pulley and surface finish.
※ 2．Diameter of both driving and driven pulley should be same.
Tt＝Te×2.14357・・・・3
Te=(m1+m2)×μ1×ｇ/η・・・・4
ｍ1：Work weight（ｋｇ）
ｍ2：Steel belt weight（ｋｇ）
μ1：Fiction coefficient of sliding surface between steel belt and support plate
 （0.3～0.6）
ｇ：Gravitational acceleration（9.807）
η：Efficiency of steel belt and roller (pulley)（0.9）
Ts=Tt－Te・・・・5
T0＝（Tt+Ts）/2・・・・6
T0：Theoretical Initial tension（N）
F＝T0×2・・・・7
F：Shaft load（N）
Shaft load which is calculated from above fomula 7, is multipled by safety factor.  And then, it is necessary to have shaft strength and frame strength which will not cause deflection or the like.However, it will be ideal to use in actual equipment as low tension as possible which will not have a problem on usage.